ACT Math: Evaluate and Compose Functions Without Confusion

Published on March 11, 2026
ACT Math: Evaluate and Compose Functions Without Confusion

The Function Notation Substitution Method

Function notation f(x) means "the output when input is x." To evaluate: (1) Identify the function rule: f(x)=2x+3. (2) Substitute the input value for every x. If asked for f(5), substitute 5: f(5)=2(5)+3=13. If asked for f(-2), substitute -2: f(-2)=2(-2)+3=-1. The key is replacing every instance of x with the given value, including in exponents and denominators.

More complex example: f(x)=x^2-4x+1. Find f(3). f(3)=3^2-4(3)+1=9-12+1=-2. Another: f(x)=1/x. Find f(1/2). f(1/2)=1/(1/2)=2. Notice how substitution works even with fractions and exponents; the rule is mechanically consistent.

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Function Composition: f(g(x)) Evaluates Inside-Out

Composition f(g(x)) means "apply g first, then apply f to the result." Work from the inside out: (1) Evaluate g(x) at the given input. (2) Take that result and plug it into f. Example: f(x)=2x+1, g(x)=x^2. Find f(g(3)). Step 1: g(3)=3^2=9. Step 2: f(9)=2(9)+1=19. Another example: Find g(f(3)). Step 1: f(3)=2(3)+1=7. Step 2: g(7)=7^2=49. Notice f(g(3))≠g(f(3)), so order matters. Write intermediate results clearly; do not try to compose in your head; errors happen fast when you skip steps.

Practice: f(x)=x+5, g(x)=3x. Find f(g(2)). g(2)=3(2)=6. f(6)=6+5=11. Find g(f(2)). f(2)=2+5=7. g(7)=3(7)=21. Different answers because composition is not commutative.

Drill: Evaluate and Compose Six Functions

f(x)=x^2+2x, g(x)=x-3, h(x)=1/x. Evaluate: 1) f(4). 2) g(-1). 3) h(2). 4) f(g(5)). 5) g(f(2)). 6) h(g(1)). For each, show your substitution step-by-step. Do this twice this week; function evaluation speed increases dramatically with repetition.

Answers: 1) f(4)=4^2+2(4)=16+8=24. 2) g(-1)=-1-3=-4. 3) h(2)=1/2. 4) g(5)=5-3=2, f(2)=2^2+2(2)=8. 5) f(2)=2^2+2(2)=8, g(8)=8-3=5. 6) g(1)=1-3=-2, h(-2)=1/(-2)=-1/2.

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Function Skills Unlock Algebra Topics on ACT Math

Function evaluation and composition are foundational for more advanced topics like inverse functions and transformations. Mastering substitution and composition takes 30 minutes of drilling and unlocks 1-2 additional points on harder problems because you can now confidently evaluate any function structure.

Commit to the six-problem drill twice this week. By test day, you will evaluate functions and compositions instantly, without hesitation.

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